Free AP Physics 1 Equation sheet

AP Physics 1 · equation sheet

AP Physics 1 Equation Sheet

The same content as the sheet you get on the exam, in our own layout. Every value in it is worked out by our math engine. The practice exams show this sheet under their Reference button.

AP Physics 1 equation sheet

The constants, conversions and equations you may look up on the AP Physics 1 exam, gathered in one place. The exam gives you a table with the same content; knowing where each equation sits, and what each symbol means, saves time when you need it.

Constants and conversion factors

QuantityValue
Universal gravitational constantGG = 6.67×10−11 m3/(kg⋅s2)6.67 \times 10^{-11}\,\mathrm{m^{3}/(kg{\cdot}s^{2})} = 6.67×10−11 N⋅m2/kg26.67 \times 10^{-11}\,\mathrm{N{\cdot}m^{2}/kg^{2}}
Acceleration due to gravity at the Earth's surface (its magnitude)gg = 9.8 m/s29.8\,\mathrm{m/s^{2}}
Gravitational field strength at the Earth's surface (its magnitude)gg = 9.8 N/kg9.8\,\mathrm{N/kg}
1 atmosphere of pressure1 atm = 1.0×105 N/m21.0 \times 10^{5}\,\mathrm{N/m^{2}} = 1.0×105 Pa1.0 \times 10^{5}\,\mathrm{Pa}

Prefixes

FactorPrefixSymbol
101210^{12}teraT
10910^{9}gigaG
10610^{6}megaM
10310^{3}kilok
10−210^{-2}centic
10−310^{-3}millim
10−610^{-6}microμ
10−910^{-9}nanon
10−1210^{-12}picop

Unit symbols

UnitSymbolUnitSymbol
hertzHznewtonN
jouleJpascalPa
kilogramkgseconds
metermwattW

Values of the trigonometric functions for common angles

The values at 37° and 53° are the rounded ones of the 3-4-5 right triangle, which the exam uses.

θ\theta0°30°37°45°53°60°90°
sin⁡θ\sin\theta012\frac{1}{2}35\frac{3}{5}22\frac{\sqrt{2}}{2}45\frac{4}{5}32\frac{\sqrt{3}}{2}1
cos⁡θ\cos\theta132\frac{\sqrt{3}}{2}45\frac{4}{5}22\frac{\sqrt{2}}{2}35\frac{3}{5}12\frac{1}{2}0
tan⁡θ\tan\theta033\frac{\sqrt{3}}{3}34\frac{3}{4}143\frac{4}{3}3\sqrt{3}∞\infty

Conventions of the exam

  • The frame of reference of any problem is inertial unless the problem says otherwise.
  • Air resistance is negligible unless the problem says otherwise.
  • Springs and strings are ideal unless the problem says otherwise.
  • Fluids are ideal, and pipes are completely filled by fluid, unless the problem says otherwise.

Geometry and trigonometry

ShapeEquations
RectangleA=bhA = bh
TriangleA=12bhA = \frac{1}{2}bh
CircleA=πr2A = \pi r^2, C=2πrC = 2\pi r, s=rθs = r\theta
Rectangular solidV=ℓwhV = \ell w h
CylinderV=πr2ℓV = \pi r^2 \ell, S=2πrℓ+2πr2S = 2\pi r\ell + 2\pi r^2
SphereV=43πr3V = \frac{4}{3}\pi r^3, S=4πr2S = 4\pi r^2
Right triangle (legs aa and bb, hypotenuse cc, θ\theta opposite aa)a2+b2=c2a^{2} + b^{2} = c^{2}, sin⁡θ=ac\sin\theta = \frac{a}{c}, cos⁡θ=bc\cos\theta = \frac{b}{c}, tan⁡θ=ab\tan\theta = \frac{a}{b}

AA is area, bb base, CC circumference, hh height, ℓ\ell length, rr radius, ss arc length, SS surface area, VV volume, ww width and θ\theta angle.

Mechanics and fluids: motion and force

EquationWhat it relates
vx=vx0+axtv_x = v_{x0} + a_x tvelocity after a time, at constant acceleration
x=x0+vx0t+12axt2x = x_0 + v_{x0}t + \frac{1}{2}a_x t^2position after a time, at constant acceleration
vx2=vx02+2ax(x−x0)v_x^2 = v_{x0}^2 + 2a_x(x - x_0)velocity and position, with no time
x⃗cm=∑mix⃗i∑mi\vec{x}_{cm} = \dfrac{\sum m_i \vec{x}_i}{\sum m_i}the center of mass
a⃗sys=∑F⃗msys=F⃗netmsys\vec{a}_{sys} = \dfrac{\sum \vec{F}}{m_{sys}} = \dfrac{\vec{F}_{net}}{m_{sys}}Newton's second law for a system
∣F⃗g∣=Gm1m2r2\lvert\vec{F}_g\rvert = G\dfrac{m_1 m_2}{r^2}the gravitational force between two masses
∣F⃗f∣≤∣μF⃗N∣\lvert\vec{F}_f\rvert \le \lvert\mu \vec{F}_N\rvertfriction (equal for kinetic friction)
F⃗s=−kΔx⃗\vec{F}_s = -k\Delta\vec{x}the spring force
ac=v2ra_c = \dfrac{v^2}{r}centripetal acceleration

Energy, power and momentum

EquationWhat it relates
K=12mv2K = \frac{1}{2}mv^2translational kinetic energy
W=F∥d=Fdcos⁡θW = F_{\parallel}d = Fd\cos\thetathe work of a constant force
ΔK=∑Wi=∑F∥,idi\Delta K = \sum W_i = \sum F_{\parallel,i}d_ithe work-energy theorem
Us=12k(Δx)2U_s = \frac{1}{2}k(\Delta x)^2the potential energy of a spring
UG=−Gm1m2rU_G = -\dfrac{Gm_1m_2}{r}gravitational potential energy of two masses
ΔUg=mgΔy\Delta U_g = mg\Delta ygravitational potential energy near the Earth
Pavg=WΔt=ΔEΔtP_{avg} = \dfrac{W}{\Delta t} = \dfrac{\Delta E}{\Delta t}average power
Pinst=F∥v=Fvcos⁡θP_{inst} = F_{\parallel}v = Fv\cos\thetainstantaneous power
p⃗=mv⃗\vec{p} = m\vec{v}momentum
F⃗net=Δp⃗Δt=mΔv⃗Δt=ma⃗\vec{F}_{net} = \dfrac{\Delta\vec{p}}{\Delta t} = m\dfrac{\Delta\vec{v}}{\Delta t} = m\vec{a}net force and the change in momentum
J⃗=F⃗avgΔt=Δp⃗\vec{J} = \vec{F}_{avg}\Delta t = \Delta\vec{p}impulse
v⃗cm=∑p⃗i∑mi=∑miv⃗i∑mi\vec{v}_{cm} = \dfrac{\sum \vec{p}_i}{\sum m_i} = \dfrac{\sum m_i\vec{v}_i}{\sum m_i}the velocity of the center of mass

Rotation

EquationWhat it relates
ω=ω0+αt\omega = \omega_0 + \alpha tangular velocity after a time, at constant angular acceleration
θ=θ0+ω0t+12αt2\theta = \theta_0 + \omega_0 t + \frac{1}{2}\alpha t^2angular position after a time
ω2=ω02+2α(θ−θ0)\omega^2 = \omega_0^2 + 2\alpha(\theta - \theta_0)angular velocity and angle, with no time
v=rωv = r\omegalinear and angular speed
aT=rαa_T = r\alphatangential and angular acceleration
τ=r⊥F=rFsin⁡θ\tau = r_{\perp}F = rF\sin\thetatorque
I=∑miri2I = \sum m_i r_i^2rotational inertia
I′=Icm+Md2I' = I_{cm} + Md^2the parallel-axis theorem
αsys=∑τIsys=τnetIsys\alpha_{sys} = \dfrac{\sum\tau}{I_{sys}} = \dfrac{\tau_{net}}{I_{sys}}Newton's second law in rotational form
K=12Iω2K = \frac{1}{2}I\omega^2rotational kinetic energy
W=τΔθW = \tau\Delta\thetathe work of a torque
L=IωL = I\omegaangular momentum of a rotating object
L=rmvsin⁡θL = rmv\sin\thetaangular momentum of a moving point mass
ΔL=τΔt\Delta L = \tau\Delta tangular impulse
Δxcm=rΔθ\Delta x_{cm} = r\Delta\thetarolling without slipping

Oscillations

EquationWhat it relates
T=1fT = \dfrac{1}{f}period and frequency
Ts=2πmkT_s = 2\pi\sqrt{\dfrac{m}{k}}the period of a mass on a spring
Tp=2πℓgT_p = 2\pi\sqrt{\dfrac{\ell}{g}}the period of a simple pendulum
x=Acos⁡(2πft)x = A\cos(2\pi ft)position in simple harmonic motion, starting at +A+A
x=Asin⁡(2πft)x = A\sin(2\pi ft)position in simple harmonic motion, starting at 0

Fluids

EquationWhat it relates
ρ=mV\rho = \dfrac{m}{V}density
P=F⊥AP = \dfrac{F_{\perp}}{A}pressure
P=P0+ρghP = P_0 + \rho ghabsolute pressure at a depth
Pgauge=ρghP_{gauge} = \rho ghgauge pressure
Fb=ρVgF_b = \rho Vgthe buoyant force
A1v1=A2v2A_1v_1 = A_2v_2continuity
P1+ρgy1+12ρv12=P2+ρgy2+12ρv22P_1 + \rho gy_1 + \frac{1}{2}\rho v_1^2 = P_2 + \rho gy_2 + \frac{1}{2}\rho v_2^2Bernoulli's equation

The symbols: aa acceleration, AA amplitude or area, dd distance, EE energy, ff frequency, FF force, hh height, II rotational inertia, JJ impulse, kk spring constant, KK kinetic energy, ℓ\ell length, LL angular momentum, mm and MM mass, pp momentum, PP power or pressure, rr radius or distance, tt time, TT period, UU potential energy, vv velocity or speed, VV volume, WW work, xx position, yy vertical position, α\alpha angular acceleration, θ\theta angle or angular position, μ\mu coefficient of friction, ρ\rho density, τ\tau torque and ω\omega angular speed.